document.write( "Question 832012: Hi,\r
\n" ); document.write( "\n" ); document.write( "PROBLEM: 3y-5/3 + y/2 = -2/3\r
\n" ); document.write( "\n" ); document.write( "How do I get rid of the fractions? I'd like a detailed solution that I can base myself on to work on other similar questions in exams. This is part of a bigger homework question but is the only part of the latter I'm actually struggling with. I'm using a method that would make it easier on me if I could clear all fractions and make everything look neater.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your time.\r
\n" ); document.write( "\n" ); document.write( "Best,\r
\n" ); document.write( "\n" ); document.write( "Anonymous
\n" ); document.write( "

Algebra.Com's Answer #501786 by erica65404(394)\"\" \"About 
You can put this solution on YOUR website!
\"3y-%285%2F3%29+%2B+y%2F2+=+-2%2F3\"
\n" ); document.write( "To get rid of fractions you need to find the least common denominator. The current denominators are 1, 3 and 2. The lowest numbers these can be factored into is 6. So we need to multiply each term by a fraction equal to 1 that will give it a new denominator of 6.\r
\n" ); document.write( "\n" ); document.write( "\"%283y%2F1%29%2A%286%2F6%29=%2818y%29%2F6\"
\n" ); document.write( "\"%28-5%2F3%29%2A%282%2F2%29=-10%2F6\"
\n" ); document.write( "\"%28y%2F2%29+%2A+%283%2F3%29+=+%283y%29%2F6\"
\n" ); document.write( "\"%28-2%2F3%29%2A%282%2F2%29=-4%2F6\"
\n" ); document.write( " now you will have the equation.
\n" ); document.write( "\"%2818y%2F6%29-%2810%2F6%29%2B%283y%2F6%29=-4%2F6\"
\n" ); document.write( "now simply solve for y.
\n" ); document.write( "\"%2821y%2F6%29-%2810%2F6%29=-4%2F6\"
\n" ); document.write( "\"%2821y%29%2F6+=+%28-4%2F6%29+%2B+%2810%2F6%29\"
\n" ); document.write( "\"%2821y%29%2F6=+6%2F6\"
\n" ); document.write( "\"y=%286%2F6%29%2F%2821%2F6%29\"
\n" ); document.write( "\"y=%286%2F6%29%2A%286%2F21%29\"
\n" ); document.write( "\"y=6%2F21\"
\n" ); document.write( "reduce.
\n" ); document.write( "\"2%2F7\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at ericahigley@yahoo.com.
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