document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831954>Question 831954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"Penelope spent all but a nickel of her $10 allowance on chocolate and bubblegum. She bought a total of 4.5 pounds of candy with chocolate costing 3.50/pound and bubblegum costing .60/pound. How much chocolate and bubblegum did she buy?\"\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you! x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501776 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> She spent $9.95 on the mixture of candy.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c for pounds of chocolate<BR>\n" );
document.write( "b for pounds of bubblegum\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c+b=4.5  accounting for pounds of the candy<BR>\n" );
document.write( "3.5c+0.6b=9.95  accounting for cost\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Modify the cost equation to have all whole numbers.<BR>\n" );
document.write( "35c+6b=99.5 ---------- NOT QUITE ALL WHOLE NUMBERS but still useful.  This was multiplying left and right by 10.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you multiply the poundage equation by 6, it becomes 6c+6b=27.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now look at the way the system is:<BR>\n" );
document.write( "6c+6b=27 and 35c+6b=99.5<BR>\n" );
document.write( "-<BR>\n" );
document.write( "Subtract the \"27\" equation from the \"99.5\" equation and this eliminates the 6b.  You will easily get a value for c.  This is the Elimination Method.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "35c+6b-(6c+6b)=99.5-27<BR>\n" );
document.write( "29c=72.5<BR>\n" );
document.write( "c=2.5 pounds for the chocolate candy<BR>\n" );
document.write( "This means b=2.0 pounds of bubblegum </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );