document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70346>Question 70346</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
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document.write( " I need help finding the surface area of a cylinder with a 10m radius and a 12m height.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50175 by </B><A HREF=/tutors/aboutme.mpl?userid=ganit><B>ganit(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganit><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> surface area of a cylinder with a 10m radius and a 12m height. <BR>\n" );
document.write( " The formula for surface area = 2 × r × pi × L + 2 × pi × r^2. <BR>\n" );
document.write( "  where r= radius and  L= height<BR>\n" );
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document.write( "  Here  r = 10 m  and L= 12 m  , pi =3.14<BR>\n" );
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document.write( "  Substituting the values in the formula<BR>\n" );
document.write( "   Surface area = 2* 10 *3.14 + 2*3.14*10 *10<BR>\n" );
document.write( "                = 62.8 + 628<BR>\n" );
document.write( "                = 690.8 sq m\r<BR>\n" );
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document.write( "    Surface area of the cylinder = 690.8 sq m </SPAN>\n" );
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