document.write( "Question 831919: The square root of -16/(3-3i)+(1-2i)
\n" ); document.write( "I know that the square rot of -16 is 4i but Idk what to do from there. PLEASE HELP!!
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Algebra.Com's Answer #501742 by stanbon(75887)\"\" \"About 
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The square root of -16/(3-3i)+(1-2i)
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\n" ); document.write( "[4i/(3-3i) + 1-2i
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\n" ); document.write( "= [(4i(3+3i)/(9+9)] + 1-2i
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\n" ); document.write( "= [4i*3(1+i)/18] + 1-2i
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\n" ); document.write( "= (2/3)(1+i) + 1 - 2i
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\n" ); document.write( "= (5/3)-(4/3)i
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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