document.write( "Question 831919: The square root of -16/(3-3i)+(1-2i)
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document.write( "I know that the square rot of -16 is 4i but Idk what to do from there. PLEASE HELP!! \n" );
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Algebra.Com's Answer #501742 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The square root of -16/(3-3i)+(1-2i) \n" ); document.write( "------ \n" ); document.write( "[4i/(3-3i) + 1-2i \n" ); document.write( "--------- \n" ); document.write( "= [(4i(3+3i)/(9+9)] + 1-2i \n" ); document.write( "------ \n" ); document.write( "= [4i*3(1+i)/18] + 1-2i \n" ); document.write( "-- \n" ); document.write( "= (2/3)(1+i) + 1 - 2i \n" ); document.write( "----- \n" ); document.write( "= (5/3)-(4/3)i \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " \n" ); document.write( " |