document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70342>Question 70342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> m^4+4m^2-12=0\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50174 by </B><A HREF=/tutors/aboutme.mpl?userid=ganit><B>ganit(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganit><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     m^4  + 4 m^2 -12 =0<BR>\n" );
document.write( "  Now find the roots of 12 <BR>\n" );
document.write( " (6,2) (4,3) In this case since product of two roots is negative one of the roots is negative. The difference between the two is 4.<BR>\n" );
document.write( " So the possible set of the roots is (6 , -2).\r<BR>\n" );
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document.write( "     m^4 + 6 m^2 -2m^2 -12 =0<BR>\n" );
document.write( "     m^2(m^2+ 6) -2(m^2 + 6) = 0<BR>\n" );
document.write( "     (m^2-2)* (m^2+6) =0  hence (m^2 -2) =0  or (m^ + 6) =0<BR>\n" );
document.write( "     m^2 = 2 or m^2 = -6<BR>\n" );
document.write( "     m= + or - sqrt(2)  or m^2 = i^2 * 6<BR>\n" );
document.write( "     m= + or - i * sqrt(6)  </SPAN>\n" );
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