document.write( "Question 831698: what is the domain of ?\r
\n" ); document.write( "\n" ); document.write( "f(x)=(x-2/x^2-4 )\r
\n" ); document.write( "\n" ); document.write( "(i've substituted parentheses for the square root symbol. just to clarify, the whole function is square rooted. thanks!)
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Algebra.Com's Answer #501735 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look for values where the function is not defined.
\n" ); document.write( "Example : When the denominator goes to zero, when the argument of a square root becomes negative.
\n" ); document.write( "In this case, you have a removable discontinuity because of the numerator.
\n" ); document.write( "\"f%28x%29=sqrt%28%28x-2%29%2F%28x%5E2-4%29%29\"
\n" ); document.write( "\"f%28x%29=sqrt%28%28x-2%29%2F%28%28x%2B2%29%28x-2%29%29%29\"
\n" ); document.write( "\"f%28x%29=sqrt%281%2F%28x%2B2%29%29\"
\n" ); document.write( "So then,
\n" ); document.write( "\"x%5E2-4=0\"
\n" ); document.write( "\"x%2B2=0\"
\n" ); document.write( "\"x=-2\"
\n" ); document.write( "Additionally,
\n" ); document.write( "\"1%2F%28x%2B2%29%3E0\"
\n" ); document.write( "\"x%2B2%3E0\"
\n" ); document.write( "\"x%3E-2\"
\n" ); document.write( "So the domain is \"x%3E-2\"
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%28%28x-2%29%2F%28x%5E2-4%29%29%29+\"
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