document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=70347>Question 70347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
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document.write( "Help! I need to find the surface area of a cone with a radius of 3in and a slant height of 5in.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #50173 by </B><A HREF=/tutors/aboutme.mpl?userid=ganit><B>ganit(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ganit><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=50173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For Cone \r<BR>\n" );
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document.write( "Lateral Surface Area = ( &#960; * R) * [sqrt(R² + H²)] <BR>\n" );
document.write( "Base Surface Area =  &#960; * R^2<BR>\n" );
document.write( "Total Surface Area = Lateral SA + Base SA <BR>\n" );
document.write( "here,\r<BR>\n" );
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document.write( "r=3 in, and slant height =5in which is same as [sqrt (r^2 + h^2) ]<BR>\n" );
document.write( "Lateral surface area =  &#960; * 3)* 5 =(3.14 *3*5) sq in = 47.1 sq in<BR>\n" );
document.write( "Base Surface Area = &#960; *r^2<BR>\n" );
document.write( "                  = 3.14 * 3*3<BR>\n" );
document.write( "                  = 28.26 sq in\r<BR>\n" );
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document.write( "Total surface area= Lateral SA + Base SA<BR>\n" );
document.write( "                  = 47.1 + 28.26<BR>\n" );
document.write( "                  = 75.36 sq in  </SPAN>\n" );
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