document.write( "Question 831847: Please help me answer this question. It would help me a lot.
\n" ); document.write( "\"In planning her retirement, Liza deposits some money at 2.5% interest, with twice as much deposited at 4%. Find the amount deposited at each rate if the total annual interest income is $1050.\" \n" ); document.write( "

Algebra.Com's Answer #501696 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
This appears to be problem of simple interest,
\n" ); document.write( "not compound interest, so I will assume that
\n" ); document.write( "Let $\"+x+\"$ = the amount invested @ 2.5% interest
\n" ); document.write( " $\"+2x+\"$ is the amount invested @ 4% interest
\n" ); document.write( "----------------------------------------
\n" ); document.write( "given:
\n" ); document.write( " $\"+.025x+%2B+.04%2A2x+=+1050+\"$
\n" ); document.write( " $\"+.025x+%2B+.08x+=+1050+\"$
\n" ); document.write( " $\"+.105x+=+1050+\"$
\n" ); document.write( " $\"+x+=+10000+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+2x+=+20000+\"$
\n" ); document.write( "$10.000 is invested @ 2.5% interest
\n" ); document.write( "$20,000 is invested @ 4% interest
\n" ); document.write( "check:
\n" ); document.write( " $\"+.025x+%2B+.08x+=+1050+\"$
\n" ); document.write( " $\"+.025%2A10000+%2B+.08%2A10000+=+1050+\"$
\n" ); document.write( " $\"+250+%2B+800+=+1050+\"$
\n" ); document.write( "OK
\n" ); document.write( " \n" ); document.write( "

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