document.write( "Question 831834: If we have 5 gallons of water and were told by a manufacturer to mix his ingredient to achieve a 15% solution. How much of the special ingredient do we need to add? \r
\n" ); document.write( "\n" ); document.write( "(I can't remember how to figure solutions .... I'm hoping you will also show the steps, so I can figure out for different amounts) \r
\n" ); document.write( "\n" ); document.write( "I know that the 5 gallons of water = 640 fluid oz \r
\n" ); document.write( "\n" ); document.write( "is it as simple as 640 + X = .15 \n" ); document.write( "
Algebra.Com's Answer #501675 by TimothyLamb(4379)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "x = gallons of ingredient
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\n" ); document.write( "0*5 + 100x = 15(x + 5)
\n" ); document.write( "100x = 15x + 75
\n" ); document.write( "85x = 75
\n" ); document.write( "x = 75/85
\n" ); document.write( "x = 0.882352941176471 gallon
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