document.write( "Question 831773: The perimeter of a rectangle is 84 feet. The ratio of the width to the length is
\n" ); document.write( "2:5. Find the length and the width. How do i set up this ratio? 2 is to 5 as x is to 84? I don't know how to set the problem up! \n" ); document.write( "
Algebra.Com's Answer #501641 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
we are given width (w)/length (l) = 2/5, now cross multiply the fraction
\n" ); document.write( "5*w = 2*l NOTE that * means multiply
\n" ); document.write( "solve for w = (2*l) / 5
\n" ); document.write( "we also know that
\n" ); document.write( "2*w + 2*l = 84
\n" ); document.write( "now substitute for w
\n" ); document.write( "2 *(2*l)/5 +2*l = 84
\n" ); document.write( "multiply both sides of = by 5
\n" ); document.write( "2*(2*l) +10*l = 420
\n" ); document.write( "14*l = 420
\n" ); document.write( "l = 30
\n" ); document.write( "substitute in perimeter equation
\n" ); document.write( "2*w + 2*30 = 84
\n" ); document.write( "divide both sides of = by 2
\n" ); document.write( "w +30 = 42
\n" ); document.write( "w = 12
\n" ); document.write( "ratio of w/l = 12/30 = 2/5
\n" ); document.write( "our answer checks :-)
\n" ); document.write( "width is 12 feet and length is 30 feet
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