document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831777>Question 831777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John has $73 in loonies and toonies. If he has 46 coins in total, how many of each coin does he have? Remember to define your variables and write a concluding statement.\r<BR>\n" );
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document.write( "     -it has to be an equation using x and y. Please help asap. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501635 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number of loonies and y be the number of toonies, then<BR>\n" );
document.write( "x +y = 46 and<BR>\n" );
document.write( "YOU must state what a loony is worth and what a toony is worth, then<BR>\n" );
document.write( "x(0.xx) +y(0.yy) = 73.00<BR>\n" );
document.write( "once you have this, you can solve first equation for x<BR>\n" );
document.write( "x = (y -46)<BR>\n" );
document.write( "then substitute for x in second equation<BR>\n" );
document.write( "(y-46)(0.xx) +y(0.yy) = 73.00<BR>\n" );
document.write( "you can solve this equation for y and then<BR>\n" );
document.write( "using first equation you can solve for x<BR>\n" );
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