document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831785>Question 831785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I'm struggling to rearrange equations with fractions. In both these equations i need to make 'a' the subject. Thanks<BR>\n" );
document.write( "1. 2b=9c/5a -7<BR>\n" );
document.write( "2. 5a=3c- 3a/c<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501634 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) 2b = 9c/5a -7<BR>\n" );
document.write( "multiply both sides of = by 5a<BR>\n" );
document.write( "10ab = 9c -35a<BR>\n" );
document.write( "add 35a to both sides of =<BR>\n" );
document.write( "10ab +35a = 9c<BR>\n" );
document.write( "5a(2b +7) = 9c<BR>\n" );
document.write( "divide both sides of = by 5(2b+7)<BR>\n" );
document.write( "a = 9c / 5(2b+7)<BR>\n" );
document.write( "2) 5a = 3c- 3a/c<BR>\n" );
document.write( "multiply both sides of = by c<BR>\n" );
document.write( "5ac = 3c^2 -3a<BR>\n" );
document.write( "add 3a to both sides of =<BR>\n" );
document.write( "5ac +3a = 3c^2<BR>\n" );
document.write( "a(5c+3) = 3c^2<BR>\n" );
document.write( "a = 3c^2 / (5c+3)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );