document.write( "Question 831784:
\n" ); document.write( "Stephanie's rectangular garden was 12 feet long and had a perimeter of 40 feet. She made her garden 6 feet longer. How could she calculate the area of her new garden?
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Algebra.Com's Answer #501623 by checkley79(3341)\"\" \"About 
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ORIGINAL LOT:
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "40=2(12+W)
\n" ); document.write( "40=24+2W
\n" ); document.write( "2W=40-24
\n" ); document.write( "2W=16
\n" ); document.write( "W=16/2
\n" ); document.write( "W=8 ANS. FOR THE WIDTH
\n" ); document.write( "NEW LOT:
\n" ); document.write( "P=2(12+6+8)
\n" ); document.write( "P=2*26=52 SQUARE FT. ANS.
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