document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831689>Question 831689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists, 56 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501575 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + 3A = 56/2 (two cyclists)<BR>\n" );
document.write( "4A = 28<BR>\n" );
document.write( "A = 7<BR>\n" );
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document.write( "The slower cyclist rides at 7mph.  In 2 hours, he travels 14 miles.<BR>\n" );
document.write( "The faster cyclist rides at 7*3mph.  In 2 hours, he travels 42 miles.<BR>\n" );
document.write( "Together, they travel 56 miles. </SPAN>\n" );
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