document.write( "Question 831689: Two cyclists, 56 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist?
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Algebra.Com's Answer #501573 by hovuquocan1997(83)![]() ![]() ![]() You can put this solution on YOUR website! Let the speed of the slow one be x \n" ); document.write( "Let the speed of the fast one be y \n" ); document.write( "Both travel and meet after 2 hours so we have the equation \n" ); document.write( "2x + 2y = 56 \n" ); document.write( "Then you have the fast one is 3 times faster than the slow one, so you have \n" ); document.write( "y = 3x =====>>>> 3x - y = 0 \n" ); document.write( "Then you solve the system of equation \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "y=21 so the speed of the faster one is 21mi/h \n" ); document.write( "TA-DAH \n" ); document.write( ":D \n" ); document.write( " |