document.write( "Question 831686: e^x-e^-x=1 Hint: multiply e^x on both sides
\n" ); document.write( "I know this involves natural log but I have no idea what to do. Please help!
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Algebra.Com's Answer #501567 by hovuquocan1997(83)\"\" \"About 
You can put this solution on YOUR website!
you have e^-x = 1/e^x (convert)
\n" ); document.write( "So the equation will become
\n" ); document.write( "e^x - 1/e^x = 1
\n" ); document.write( "multiply e^x like you said
\n" ); document.write( "\"e%5Ex%2Ae%5Ex+-+1+=+e%5Ex\"
\n" ); document.write( "\"%28e%5Ex%29%5E2+-+e%5Ex+-+1+=+0\"
\n" ); document.write( "Then you can let e^x = a and the equation will become
\n" ); document.write( "\"a%5E2+-+a+-+1+=+0\"
\n" ); document.write( "You can solve this equation using quadratic formula, then you will get two answer
\n" ); document.write( "\"a\" = \"%281%2Bsqrt%285%29%29%2F2\"
\n" ); document.write( "and \"a\" = \"%281-sqrt%285%29%29%2F2\"
\n" ); document.write( "Remember you let e^x = a? Now change a into e^x
\n" ); document.write( "You have \"e%5Ex\" = \"%281%2Bsqrt%285%29%29%2F2\"
\n" ); document.write( "Then you use natural log on both side, you will have
\n" ); document.write( "\"x\" = \"ln%28%281%2Bsqrt%285%29%29%2F2%29\" and then use calculator to find it
\n" ); document.write( "And then you find another answer with \"e%5Ex\" = \"%281-sqrt%285%29%29%2F2\" using the same method
\n" ); document.write( "TA-DAH
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