document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831683>Question 831683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 60.One number is 16 more than twice the other number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501564 by </B><A HREF=/tutors/aboutme.mpl?userid=hovuquocan1997><B>hovuquocan1997(83)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hovuquocan1997><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let's the second number be x, the first number is 16 more than twice the second number, so it will be 2x+16 <BR>\n" );
document.write( "The sum of two number is 60, means x + 2x + 16 = 60<BR>\n" );
document.write( "3x = 44<BR>\n" );
document.write( "x = 44/3 <BR>\n" );
document.write( "So one number is 44/3 and the other one is 2*44/3 + 16 = 136/3<BR>\n" );
document.write( "TA-DAH <BR>\n" );
document.write( ":D  </SPAN>\n" );
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