document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831625>Question 831625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Elimination <BR>\n" );
document.write( "3y=x+5 <BR>\n" );
document.write( "-3x+8y=8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501556 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Easier to arrange into both the same form.\r<BR>\n" );
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document.write( "3y=x+5<BR>\n" );
document.write( "3y+(-x)=x+5+(-x)<BR>\n" );
document.write( "-x+3y=x+(-x)+5<BR>\n" );
document.write( "-x+3y=0+5<BR>\n" );
document.write( "-x+3y=5.\r<BR>\n" );
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document.write( "The other equation is already in the same (standard) form.  Easiest choice of factor to use for the transformed first equation is NEGATIVE 3.  You would then add the two equations.  This will eliminate x terms. </SPAN>\n" );
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