document.write( "Question 831546: A mechanic is working on a car with a 20-qt radiator containing a 60% antifreeze solution. How much of the solution should he drain and replace with pure water to get a solution that is 50% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #501499 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" = quarts of solution that musty be drained
\n" ); document.write( "and replaced with pure water
\n" ); document.write( "\"+.6x+\" = quarts of pure antifreeze in the solution
\n" ); document.write( "that is drained from radiator
\n" ); document.write( "\"+.6%2A20+=+12+\" = quarts of pure antifreeze originally
\n" ); document.write( "in the radiator
\n" ); document.write( "-------------------------
\n" ); document.write( "\"+%28+12+-+.6x+%29+%2F+20+=+.5+\"
\n" ); document.write( "\"+12+-+.6x+=+.5%2A20+\"
\n" ); document.write( "\"+12+-+.6x+=+10+\"
\n" ); document.write( "\"+.6x+=+12+-+10+\"
\n" ); document.write( "\"+.6x+=+2+\"
\n" ); document.write( "\"+x+=+3.333+\"
\n" ); document.write( "3.333 quarts of the solution should he drained and replaced
\n" ); document.write( "with pure water to get a solution that is 50% antifreeze
\n" ); document.write( "-------------------
\n" ); document.write( "check answer:
\n" ); document.write( "\"+.6%2A3.333+=+2+\" quarts of pure antifreeze is drained
\n" ); document.write( "There is \"+.6%2A20+-+2+\"
\n" ); document.write( "\"+12+-+2+=+10+\" quarts of pure antifreeze left
\n" ); document.write( "The concentration after the \"4\" quarts of water is
\n" ); document.write( "poured in is:
\n" ); document.write( "\"+10%2F20+=+.5+\"
\n" ); document.write( "\"+.5%2A100+\" = 50% antifreeze
\n" ); document.write( "OK
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