document.write( "Question 831550: The perimeter of a rectangle is 48 centimeters. The width is three more than twice the length. Find the length and width \n" ); document.write( "
Algebra.Com's Answer #501461 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
A perimeter is a fence. How much fencing do you need to go around a rectangle?
\n" ); document.write( "P = 2W + 2L (you'll need two pieces of length + 2 pieces of width)
\n" ); document.write( "Given:
\n" ); document.write( "P = 48
\n" ); document.write( "W = 2L + 3
\n" ); document.write( ".
\n" ); document.write( "Plug those into the original equation:
\n" ); document.write( "48 = 2L + 2(2L + 3) [substituted the value of the width for W]
\n" ); document.write( "48 = 2L +4L + 6
\n" ); document.write( "Add the Ls
\n" ); document.write( "48 = 6L + 6
\n" ); document.write( "Subtract 6 from each side
\n" ); document.write( "42 = 6L
\n" ); document.write( "Divide each side by 6
\n" ); document.write( "7 = L <<--
\n" ); document.write( "If the length is 7, and we know the width is 3 more than twice the length, the width must be (7*2)+3, or 17
\n" ); document.write( ".
\n" ); document.write( "Let's see if that works.
\n" ); document.write( "48 = 2(7) + 2(17)
\n" ); document.write( "48 = 14 + 34
\n" ); document.write( "Success!
\n" ); document.write( " \n" ); document.write( "
\n" );