document.write( "Question 831441: A backyard swimming pool has two fill pipes and a drain pipe. The pool fills in 9 hours with the first fill pipe. Draining the pool with the drain pipe takes 1 hour longer than filling the pool with the second fill pipe. If all three pipes are open at once, the pool can be filled in 8 hours. How many hours would draining the pool take with the two fill pipes closed? \n" ); document.write( "
Algebra.Com's Answer #501455 by ankor@dixie-net.com(22740)\"\" \"About 
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A backyard swimming pool has two fill pipes and a drain pipe.
\n" ); document.write( " The pool fills in 9 hours with the first fill pipe.
\n" ); document.write( " Draining the pool with the drain pipe takes 1 hour longer than filling the pool with the second fill pipe.
\n" ); document.write( " If all three pipes are open at once, the pool can be filled in 8 hours.
\n" ); document.write( " How many hours would draining the pool take with the two fill pipes closed?
\n" ); document.write( ":
\n" ); document.write( "let d = time for the drain to empty the pool, when the other two pipes are closed.
\n" ); document.write( "then
\n" ); document.write( "(d-1) = time for the 2nd pipe to fill the pool
\n" ); document.write( ":
\n" ); document.write( "Let the filled pool = 1
\n" ); document.write( "\"8%2F9\" + \"8%2F%28%28d-1%29%29\" - \"8%2Fd\" = 1
\n" ); document.write( "multiply equation by 9d(d-1), cancel the denominators, resulting in
\n" ); document.write( "8d(d-1) + 9d(8) - 9(d-1)(8) = 9d(d-1)
\n" ); document.write( "8d^2 - 8d + 72d - 72d + 72 = 9d^2 - 9d
\n" ); document.write( "8d^2 - 8d + 72 = 9d^2 - 9d
\n" ); document.write( "combine like terms on the right
\n" ); document.write( "0 = 9d^2 - 8d^2 - 9d + 8d - 72
\n" ); document.write( "d^2 - d - 72 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(d-9(d+8) = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "d = 9 hrs to drain the pool
\n" ); document.write( ":
\n" ); document.write( "See if the works
\n" ); document.write( "\"8%2F9\" + \"8%2F8\" - \"8%2F9\" = 1; looks OK
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