document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831539>Question 831539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution of 1/4x-5=3/4x-12 ? Please explain your steps and how you got it. I dont understand how to figure it out. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501452 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pesky fractions!<BR>\n" );
document.write( "Let's get rid of them.  Multiply each side by 4.<BR>\n" );
document.write( "(1/4x - 5) * 4 = 4/4x - 20 = x-20<BR>\n" );
document.write( "The other side: (3/4x-12) * 4 = 12/4x - 48 = 3x-48<BR>\n" );
document.write( "Now plug those back in.<BR>\n" );
document.write( "x-20 = 3x-48<BR>\n" );
document.write( "Subtract x from each side<BR>\n" );
document.write( "-20 = 2x - 48<BR>\n" );
document.write( "Add 48 to each side<BR>\n" );
document.write( "28 = 2x<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "14 = x <<--<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let's check it to be certain, by using the original question.<BR>\n" );
document.write( "1/4x-5=3/4x-12<BR>\n" );
document.write( "(1/4 * 14)-5 = (3/4 * 14) - 12<BR>\n" );
document.write( "14/4 - 5 = 42/4 - 12<BR>\n" );
document.write( "3.5 - 5 = 10.5 - 12<BR>\n" );
document.write( "-1.5 = - 1.5<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );