document.write( "Question 831528: Hi, \r
\n" ); document.write( "\n" ); document.write( "any help with these questions would be gratefully received.\r
\n" ); document.write( "\n" ); document.write( "Many thanks, \r
\n" ); document.write( "\n" ); document.write( "Hugh.\r
\n" ); document.write( "\n" ); document.write( "Question 1. \r
\n" ); document.write( "\n" ); document.write( "Find the gradient of the straight line with equation 16x + 4y = 2.\r
\n" ); document.write( "\n" ); document.write( "Question 2.\r
\n" ); document.write( "\n" ); document.write( "b = 3-a/2\r
\n" ); document.write( "\n" ); document.write( "rearranged to make a the subject of the equation.
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Algebra.Com's Answer #501447 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Put the equation in slope-intercept form, \"y=mx%2Bb\"
\n" ); document.write( "\"m\"} is the slope or gradient.
\n" ); document.write( "\"16x%2B4y=2\"
\n" ); document.write( "\"4y=-16x%2B2\"
\n" ); document.write( "\"y=-4x%2B1%2F2\"
\n" ); document.write( "\"m=-4\"
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\n" ); document.write( "\"b=3-a%2F2\" or \"b=%283-a%29%2F2\"
\n" ); document.write( "\"a%2F2=3-b\" or \"2b=3-a\"
\n" ); document.write( "\"a=2%283-b%29\" or \"a=3-2b\"\r
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