document.write( "Question 831506: Suppose the length of a certain rectangle is 5 meters more than twice its width and the perimeter is 22 meters. The width must be ___ meters? \n" ); document.write( "
Algebra.Com's Answer #501422 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Remember that the perimeter is a fence. You'll need two pieces of length and two pieces of width. 2L + 2W = P \n" ); document.write( "The problem gives you the following: \n" ); document.write( "P = 22 \n" ); document.write( "L = 2W + 5 (\"length of a certain rectangle is 5 meters more than twice its width\") \n" ); document.write( ". \n" ); document.write( "Substitute the value of L into the root equation \n" ); document.write( "2(2W + 5) + 2W = P \n" ); document.write( "Distribute \n" ); document.write( "4W +10 + 2W = 22 \n" ); document.write( "Add the Ws \n" ); document.write( "6W + 10 = 22 \n" ); document.write( "Subtract 10 from each side \n" ); document.write( "6W = 12 \n" ); document.write( "Divide each side by 6 \n" ); document.write( "W = 2 <<-- \n" ); document.write( ". \n" ); document.write( "Let's plug it back into the original question to make certain. \n" ); document.write( "\"Suppose the length of a certain rectangle is 5 meters more than twice its width [(2*2)+5 = 9] and the perimeter is 22 meters\" \n" ); document.write( "Then we'd have 2 pieces of 9' and 2 pieces of 2'. 9+9+2+2 = 22 \n" ); document.write( "Success! \n" ); document.write( " |