document.write( "Question 831460: What is the equation of the line through the point (−1/2,−2) and perpendicular to the line corresponding the equation 2x+7y=−15? \n" ); document.write( "
Algebra.Com's Answer #501364 by hovuquocan1997(83)\"\" \"About 
You can put this solution on YOUR website!
First, you need the change the given equation into standard form.
\n" ); document.write( "2x+7y=-15
\n" ); document.write( "7y = -2x - 15
\n" ); document.write( "y = (-2/7)x - 15/7
\n" ); document.write( "The linear equation you are finding has a form like this also y = ax + b
\n" ); document.write( "In order to be perpendicular, the a of this equation you are finding and the a in the given equation must multiply together and give you - 1, so you have
\n" ); document.write( "(-2/7)a = -1
\n" ); document.write( "a = 7/2 \r
\n" ); document.write( "\n" ); document.write( "So now you have the a, let's plug it in and have y = (7/2)x + b
\n" ); document.write( "Now you have the point (-1/2,-2) on this line, -1/2 is x and -2 is y, so you plug it in
\n" ); document.write( "-2 = (7/2)*(-1/2) + b
\n" ); document.write( "-2 = (-7/4) + b
\n" ); document.write( "-2 + 7/4 = b
\n" ); document.write( "-1/4 = b
\n" ); document.write( "TA-DAH
\n" ); document.write( "Your answer is y = (7/2)x - 1/4\r
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