document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831458>Question 831458</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this : Line JK has endpoints J(4,6) and K(0,2). The intersection of  Line JK and its perpendicular bisector is (2,4) . Write the equation for the perpendicular bisector of line JK.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501361 by </B><A HREF=/tutors/aboutme.mpl?userid=hovuquocan1997><B>hovuquocan1997(83)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hovuquocan1997><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501361\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, because you have 3 points for line JK, which is (4,6), (0,2) you should start finding the equation for this line first in order to find the perpendicular line. A linear equation has a formula like this y=ax + b<BR>\n" );
document.write( "Create a system of two equations: <BR>\n" );
document.write( "First: 6=4a+b <BR>\n" );
document.write( "Second: 2=0a+b<BR>\n" );
document.write( "So you have system of 2 equations: <BR>\n" );
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document.write( " <TR><TD  ALIGN=MIDDLE>Solved by <A  rel=nofollow HREF=http://wiki.algebra.com/index.php/Tutoring_-_pluggable_solvers>pluggable</A> solver: <A  rel=nofollow HREF=linear.solver>Linear System solver (using determinant)</A></TD></TR>\n" );
document.write( "<TR><TD  ALIGN=LEFT>Solve:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++4%5Ca+%2B+1%5Cb+=+6%2C%0D%0A++++0%5Ca+%2B+1%5Cb+=+2+%29%0D%0A++ ALIGN=MIDDLE  ALT=\"+system%28+%0D%0A++++4%5Ca+%2B+1%5Cb+=+6%2C%0D%0A++++0%5Ca+%2B+1%5Cb+=+2+%29%0D%0A++\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  Any system of equations:<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++a%5B11%5D%2Aa+%2B+a%5B12%5D%2Ab+=+b%5B1%5D%2C%0D%0A++++a%5B21%5D%2Aa+%2B+a%5B22%5D%2Ab+=+b%5B2%5D%29%0D%0A++ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  has solution<BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++a+=+%28b%5B1%5D%2Aa%5B22%5D+-+b%5B2%5D%2Aa%5B12%5D%29%2F%28a%5B11%5D%2Aa%5B22%5D-a%5B21%5D%2Aa%5B12%5D%29%2C%0D%0A++++b+=+%28a%5B11%5D%2Ab%5B2%5D+-+a%5B21%5D%2Ab%5B1%5D%29%2F%28a%5B11%5D%2Aa%5B22%5D-a%5B21%5D%2Aa%5B12%5D%29%0D%0A++++%29%0D%0A++ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  or<BR>\n" );
document.write( "  <BR>\n" );
document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+system%28+%0D%0A++++++a+=+%286%2A1+-+2%2A1%29%2F%284%2A1-0%2A1%29+=+1%2C%0D%0A++++++b+=+%284%2A2+-+0%2A6%29%2F%284%2A1-0%2A1%29+=+2%0D%0A++++%29%0D%0A++ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "  <BR>\n" );
document.write( "  (a=1, b=2}<BR>\n" );
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document.write( "Then you can find a=1 and b=2<BR>\n" );
document.write( "So the equation would be : y=1x + 2 which is y = x + 2<BR>\n" );
document.write( "Now let's find the perpendicular line. it also has the equation form like this <BR>\n" );
document.write( "Y = ax + b<BR>\n" );
document.write( "But in order to be perpendicular with JK, the a in this equation and the a in JK equation must multiply together and give you -1<BR>\n" );
document.write( "so 1.a = -1 ===> a = -1<BR>\n" );
document.write( "So you have y = -x + b<BR>\n" );
document.write( "Now you have point (2,4) given on the line in the question. PLUG IT IN<BR>\n" );
document.write( "4 = -(2) + b<BR>\n" );
document.write( "b = 6 <BR>\n" );
document.write( "TA-DAH. You have the equation y = -x + 6 :D <BR>\n" );
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