document.write( "Question 831443: How do you solve \"log'5'81 = 2log'5'x\r
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Algebra.Com's Answer #501357 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"log%285%2C81%29=2%2Alog%285%2Cx%29\"
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\n" ); document.write( "\"81=x%5E2\"
\n" ); document.write( "\"highlight%28x=9%29\"
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