document.write( "Question 831122: A cylindrical jar of radius 3cm contains water to depth of 5cm. The water is then poured at a steady rate into an inverted conical container with its axis vertical. After t seconds, the depth of water in this container is x cm and the volume, V ml, of water that has been transferred is given by V= 1/3 (pie)(x)(x)(x).
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document.write( "Given that all the water is transferred in 3 seconds,find
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document.write( "a) dv/dt in terms of pie
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document.write( "b) the rate at which c is increasing at the moment when x= 2.5 \n" );
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Algebra.Com's Answer #501353 by KMST(5328)![]() ![]() You can put this solution on YOUR website! The volume in that cylindrical jar, calculated as \n" ); document.write( "is \n" ); document.write( " \n" ); document.write( "a) If that volume is transferred at a steady rate in \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "b) Since there is no \"c\" mentioned in the problem before part b), \n" ); document.write( "I assume that the question for part b) was \n" ); document.write( "to find the rate (maybe called c) at which the water level is increasing in the inverted conical container, \n" ); document.write( "when that water level there is \n" ); document.write( "That rate would be \n" ); document.write( "At a constant rate of \n" ); document.write( "We also know that \n" ); document.write( "We can use those two equations to find \n" ); document.write( "I believe the easiest way to find the value of \n" ); document.write( " \n" ); document.write( "We know that \n" ); document.write( "and from \n" ); document.write( " \n" ); document.write( "When \n" ); document.write( "so at that point \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That does not give me a general expression for \n" ); document.write( "However, just for fun, let's try to solve that way. \n" ); document.write( "With your excuse, I will skip writting the units this time. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That still does not look pretty, but I cannot make improve it too much, so I let it be. \n" ); document.write( "When \n" ); document.write( "Substituting into \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So we get to the same result, and we have |