document.write( "Question 831391: Please help me solve this equation:
\n" ); document.write( "In going over a round trip of 40 km each way, it takes a course travelling 12 kph in still water, having a total time of 7 hours and a half. What was the rate of the river current?
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Algebra.Com's Answer #501341 by KMST(5328)\"\" \"About 
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Your boat travels at 12 kilometers per hour in still water.
\n" ); document.write( "In a river with a current flowing at a speed of \"x\" kilometers per hour,
\n" ); document.write( "the boat will advance (as seen from the shore) at \"%2812-x%29\" kph when going upstream, against the current.
\n" ); document.write( "When going downstream, the boat will move at \"%2812%2Bx%29\" kph relative to the shore.
\n" ); document.write( "The 40 kilometer trip upstream will take
\n" ); document.write( "\"40%2F%2812-x%29\" hours.
\n" ); document.write( "The 40 kilometer trip downstream will take
\n" ); document.write( "\"40%2F%2812%2Bx%29\" hours.
\n" ); document.write( "Adding those times we would get the total time of \"7.5\" hours, so our equation is
\n" ); document.write( "\"40%2F%2812-x%29%2B40%2F%2812%2Bx%29=7.5\"
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\n" ); document.write( "Solving:
\n" ); document.write( "\"40%2F%2812-x%29%2B40%2F%2812%2Bx%29=7.5\"
\n" ); document.write( "
\n" ); document.write( "\"%28480%2B40x%29%2F%28144-x%5E2%29%2B%28480-40x%29%2F%28144-x%5E2%29=7.5\"
\n" ); document.write( "\"%28480%2B40x%2B480-40x%29%2F%28144-x%5E2%29=7.5\"
\n" ); document.write( "\"960%2F%28144-x%5E2%29=7.5\"
\n" ); document.write( "\"960=7.5%28144-x%5E2%29\"
\n" ); document.write( "\"960=1080-7.5x%5E2\"
\n" ); document.write( "\"7.5x%5E2=1080-960\"
\n" ); document.write( "\"7.5x%5E2=120\"
\n" ); document.write( "\"x%5E2=120%2F7.5\"
\n" ); document.write( "\"x%5E2=16\"
\n" ); document.write( "Since we measured the rate of the current in the direction of the flow as a positive number,
\n" ); document.write( "\"highlight%28x=sqrt%2816%29=4%29\" .
\n" ); document.write( "The rate of the current is \"highlight%284kph%29\" .
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