document.write( "Question 831410: i got this matrix :
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document.write( " 3 0 0 -1
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document.write( " 0 2 -2 1
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document.write( "-3 3 -2 2
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document.write( " 6 1 0 1\r
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document.write( "i want to find the determinant, i got this :
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document.write( " |2 -2 1| | 0 2 -2|
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document.write( "3 |3 -2 2|- 0 + 0 + |-3 3 -2|
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document.write( " |1 0 1| | 6 1 0|\r
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document.write( "and got 3((2x-2)+(2x1)+2)+(42+42) = 84 ?
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document.write( "where do i got wrong ? \n" );
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Algebra.Com's Answer #501339 by AnlytcPhil(1807) You can put this solution on YOUR website! \r\n" ); document.write( "Don't listen to him. You can't stop and go \"PDF-ing\" everytime you need \r\n" ); document.write( "to do a small problem. \r\n" ); document.write( "\r\n" ); document.write( "First get a 0 in the upper left corner by multiplying the 4th column by 3\r\n" ); document.write( "and adding it to the first column. \r\n" ); document.write( " \r\n" ); document.write( "| 3 0 0 -1| | 0 0 0 -1| | 3 2 -2| | 3 2 -2|\r\n" ); document.write( "| 0 2 -2 1| 3C4+C1->C1 | 3 2 -2 1| = -(-1)| 3 3 -2| = | 3 3 -2|\r\n" ); document.write( "|-3 3 -2 2| | 3 3 -2 2| | 9 1 0| | 9 1 0|\r\n" ); document.write( "| 6 1 0 1| | 9 1 0 1|\r\n" ); document.write( "\r\n" ); document.write( "When you get down to a 3×3 determinant, it's often too tedious to\r\n" ); document.write( "always expand it by minors. I'm sure your error was a sign or \r\n" ); document.write( "something. Expand by minors until you get down to a 3×3, then\r\n" ); document.write( "do the 3×3 this following way. You're less likely to make a mistake.\r\n" ); document.write( "Copy the first two columns over to the right of the determinant\r\n" ); document.write( "\r\n" ); document.write( "| 3 2 -2| 3 2\r\n" ); document.write( "| 3 3 -2| 3 3\r\n" ); document.write( "| 9 1 0| 9 1\r\n" ); document.write( "\r\n" ); document.write( "Then multiply the three diagonals that slant this way \ and add them:\r\n" ); document.write( "\r\n" ); document.write( "(3)(3)(0) + (2)(-2)(9) + (-2)(3)(1) = 0-36-6 = -42\r\n" ); document.write( "\r\n" ); document.write( "Then multiply the three diagonals that slant this way / and add them\r\n" ); document.write( "\r\n" ); document.write( "(-2)(3)(9) + (3)(-2)(1) + (-2)(3)(0) = -54 - 6 - 0 = -60\r\n" ); document.write( "\r\n" ); document.write( "Then subtract (-42)-(-60) = -42 + 60 = 18\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |