document.write( "Question 831292: Solve each equation. Remember to check for extraneous solutions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "8x-40/(2x^2-x-3) + 8x-8/(2x^2-x-3) = 6/(x+1) \n" ); document.write( "

Algebra.Com's Answer #501314 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%288x-40%29%2F%282x%5E2-x-3%29++%2B++%288x-8%29%2F%282x%5E2-x-3%29+++=++6%2F%28x%2B1%29\"$
\n" ); document.write( " $\"+%288x-40%2B8x-8%29%2F%282x%5E2-x-3%29+++=++6%2F%28x%2B1%29\"$
\n" ); document.write( " $\"+%2816x-48%29%2F%282x%5E2-x-3%29+++=++6%2F%28x%2B1%29\"$
\n" ); document.write( " $\"+%2816%28x-3%29%29%2F%282x%5E2-x-3%29+++=++6%2F%28x%2B1%29\"$
\n" ); document.write( " $\"+%288%28x-3%29%29%2F%28%28x%2B1%29%282x-3%29%29+++=++3%2F%28x%2B1%29\"$
\n" ); document.write( " $\"+%288%28x-3%29%29%2F%282x-3%29+++=++3\"$
\n" ); document.write( " $\"+%288%28x-3%29%29=3%282x-3%29+\"$
\n" ); document.write( " $\"8x-24=6x-9\"$
\n" ); document.write( " $\"2x=-15\"$
\n" ); document.write( " $\"highlight%28x=-15%2F2%29\"$
\n" ); document.write( " \n" ); document.write( "

\n" );