document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831408>Question 831408</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what dimensions of a tin  can of volume 54 pie cm^3 should be produced if the required height is equal to the diameter of its base </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501305 by </B><A HREF=/tutors/aboutme.mpl?userid=Elomeht><B>Elomeht(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Elomeht><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501305\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  The volume of the can (assumed cylindrical) is given by the formula:<BR>\n" );
document.write( "    V = PI (r^2) h where r is the radius of the base and h is the height\r<BR>\n" );
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document.write( "2.  Since the height is equal to the diameter of the base (i.e. 2r), we can modify<BR>\n" );
document.write( "    the formula to read:<BR>\n" );
document.write( "    V = PI (r^2)2r = 2PI (r^3)\r<BR>\n" );
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document.write( "3.  We are told that the volume of the can is 54PI cubic centimeters, so we can put:<BR>\n" );
document.write( "    54PI = 2PI (r^3)\r<BR>\n" );
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document.write( "4.  From the above, 27 = (r^3), so r = 3\r<BR>\n" );
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document.write( "5.  The diameter of the base is therefore 6, which is the same as the height<BR>\n" );
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