document.write( "Question 70146This question is from textbook College Algebra Essentials
\n" ); document.write( ": square root 3 * square root x + 1 = square root 3x - 5 \n" ); document.write( "
Algebra.Com's Answer #50128 by ankor@dixie-net.com(22740)\"\" \"About 
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square root 3 * square root x + 1 = square root 3x - 5
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\n" ); document.write( "Assume you mean:
\n" ); document.write( "Sqrt(3)* Sqrt(x) + 1 = Sqrt(3x) - 5
\n" ); document.write( ":
\n" ); document.write( "Sqrt(3x) = Sqrt(3x) - 5 - 1
\n" ); document.write( "Sqrt(3x) = Sqrt(3x) - 6
\n" ); document.write( ":
\n" ); document.write( "Square both sides, FOIL (Sqrt(3x) - 6)^2:
\n" ); document.write( "3x = 3x - 12Sqrt(3x) + 36
\n" ); document.write( "3x - 3x - 36 = -12Sqrt(3x)
\n" ); document.write( "-36 = -12Sqrt(3x)
\n" ); document.write( ":
\n" ); document.write( "Mult eq by -1, get rid of the negatives:
\n" ); document.write( "36 = 12Sqrt(3x)
\n" ); document.write( ":
\n" ); document.write( "Square both sides:
\n" ); document.write( "1296 = 144(3x)
\n" ); document.write( "1296 = 432x
\n" ); document.write( "x = 1296/433
\n" ); document.write( "x = 3
\n" ); document.write( ":
\n" ); document.write( "Check solution in original equation
\n" ); document.write( "Sqrt(3)* Sqrt(x)+ 1 = Sqrt(3x) - 5
\n" ); document.write( "Sqrt(3)* Sqrt(3)+ 1 = Sqrt(3*3) - 5
\n" ); document.write( "3 + 1 = 9 - 5
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