document.write( "Question 831288: You invested $7000 in two accounts paying 7% and 8% annual interest, respectively. If the total interest earned for the year was $537, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #501263 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 7.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 8.00% per annum ------------ Amount invested = y \n" ); document.write( " 7000 \n" ); document.write( "Interest----- 537.00 \n" ); document.write( " \n" ); document.write( "Part I 7.00% per annum ---x \n" ); document.write( "Part II 8.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 7000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "7.00% x + 8.00% y= 537 \n" ); document.write( "Multiply by 100 \n" ); document.write( "7 x + 8 y= 53700.00 --------2 \n" ); document.write( "Multiply (1) by -7 \n" ); document.write( "we get \n" ); document.write( "-7 x -7 y= -49000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 1 y= 4700 \n" ); document.write( "divide by 1 \n" ); document.write( " y = 4700 \n" ); document.write( "Part I 7.00% $ 2300 \n" ); document.write( "Part II 8.00% $ 4700 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "2300 --------- 7.00% ------- 161.00 \n" ); document.write( "4700 ------------- 8.00% ------- 376.00 \n" ); document.write( "Total -------------------- 537.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |