document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831329>Question 831329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many (#) .45 inch spheres to fill a 3 inch dia. by 4 inch high cylinder ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501261 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many (#) 0.45 inch spheres to fill a 3 inch dia. by 4 inch high cylinder ?<BR>\n" );
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document.write( "# accommodated by the height:: 4\"/(0.45) = 8.89;; round down to 8<BR>\n" );
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document.write( "# accommodated by the cross-section:<BR>\n" );
document.write( "Cross-section of the cylinder: pi*1.5^2 = 7.07 in^2<BR>\n" );
document.write( "Cross-section of a sphere:: pi*0.225^2 = 0.159<BR>\n" );
document.write( "# accommodated by the cross-section = 7.07/0.159 = 44.45; round down to 44<BR>\n" );
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document.write( "Ans: # of spheres accommodated by the cylinder: 44*8 352k<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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