document.write( "Question 831338: divide 105in to two parts in which the first half part exceeds the one fifth of the second by 35'kindlygive me its step also \n" ); document.write( "
Algebra.Com's Answer #501247 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! divide 105in to two parts in which the first half part exceeds the one fifth of the second by 35\" \n" ); document.write( "----------------------- \n" ); document.write( "x + y = 105\" \n" ); document.write( "y-(1/5)x = 35 \n" ); document.write( "-------------------- \n" ); document.write( "Substitute for \"y\" and solve for \"x\": \n" ); document.write( "x + (1/5)x +35 = 105 \n" ); document.write( "(6/5)x = 70 \n" ); document.write( "x = (5/6)70 \n" ); document.write( "--- \n" ); document.write( "x = 350/6 \n" ); document.write( "x = 58 1/3\" \n" ); document.write( "--------------- \n" ); document.write( "y = 105 - 58 1/3 = 46 2/3 inches \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |