document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831290>Question 831290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of the rectangular tennis court at Wimbledon is 2 feet longer than twice the width. If the court's perimeter is 238 feet, what are the court's dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501232 by </B><A HREF=/tutors/aboutme.mpl?userid=jgr45><B>jgr45(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jgr45><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jgr45><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501232\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, understand what a perimeter is.  It is the total distance around the borders of the court.  That said, begin by translating to algebraic expressions.  This will be a system of two equations:\r<BR>\n" );
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document.write( "L = 2W + 2<BR>\n" );
document.write( "2L + 2W = 238\r<BR>\n" );
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document.write( "First, begin by substituting 2w+2 for L:\r<BR>\n" );
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document.write( "2(2w+2) + 2w = 238<BR>\n" );
document.write( "4w + 4 + 2w = 238<BR>\n" );
document.write( "6w + 4 = 238<BR>\n" );
document.write( "6w = 234<BR>\n" );
document.write( "w = 39<BR>\n" );
document.write( "L = 2(39) + 2<BR>\n" );
document.write( "L = 78 + 2<BR>\n" );
document.write( "L = 80\r<BR>\n" );
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document.write( "So your court dimensions are 80' by 39'. </SPAN>\n" );
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