document.write( "Question 831258: Matt and Ming are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. Matt sold 3 small(?) boxes of oranges and 14 large boxes of oranges for a total of $203. Ming sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost each of one small box of oranges and one large box of oranges. \n" ); document.write( "
Algebra.Com's Answer #501218 by jgr45(31)![]() ![]() You can put this solution on YOUR website! What you need to do here is somehow isolate one of the variables.\r \n" ); document.write( "\n" ); document.write( "3x + 14y = 203 \n" ); document.write( "11x + 11y = 220\r \n" ); document.write( "\n" ); document.write( "What I would do here is first of all divide the bottom equation by 11: \n" ); document.write( "x + y = 20\r \n" ); document.write( "\n" ); document.write( "Now get one variable by itself. Either one works; I'll choose y. \n" ); document.write( "y = 20 - x\r \n" ); document.write( "\n" ); document.write( "Now substitute 20-x for y in either equation. I'll pick the first one. \n" ); document.write( "3x + 14(20-x) = 203 \n" ); document.write( "3x + 280 - 14x = 203 \n" ); document.write( "280 - 11x = 203 \n" ); document.write( "280 = 203 + 11x \n" ); document.write( "77 = 11x \n" ); document.write( "x = 7\r \n" ); document.write( "\n" ); document.write( "Which means y = 20-7 or 13.\r \n" ); document.write( "\n" ); document.write( "So your prices are $7 for the small boxes and $13 for the large.\r \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "3(7) + 14(13) =? 203 and 11(7) + 11(13) =? 220 \n" ); document.write( "21 + 182 =? 203 and 77 + 143 =? 220 \n" ); document.write( "203=203 and 220=220 \n" ); document.write( " \n" ); document.write( " |