document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831258>Question 831258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Matt and Ming are selling fruit for a school fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. Matt sold 3 small(?) boxes of oranges and 14 large boxes of oranges for a total of $203. Ming sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost each of one small box of oranges and one large box of oranges. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501217 by </B><A HREF=/tutors/aboutme.mpl?userid=Elomeht><B>Elomeht(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Elomeht><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.  3x + 14y = 203<BR>\n" );
document.write( "2.  11x + 11y = 220\r<BR>\n" );
document.write( "\n" );
document.write( "3.  Divide the last equation above by 11:  x + y = 20<BR>\n" );
document.write( "4.  This is the same as saying x = 20 - y\r<BR>\n" );
document.write( "\n" );
document.write( "5.  Now, substitute for x in the first equation:  3(20 - y) + 14y = 203<BR>\n" );
document.write( "6.  The above equation simplifies to 60 - 3y + 14y = 203<BR>\n" );
document.write( "7.  Now express the equation in terms of y:  11y = 143\r<BR>\n" );
document.write( "\n" );
document.write( "8.  From the last equation, y = 13<BR>\n" );
document.write( "9.  Since x + y = 20, x = 7<BR>\n" );
document.write( "10.  Check:  (3 times 7) + (14 times 13) = 21 + 182 = 203; <BR>\n" );
document.write( "             (11 times 7) + (11 times 13) = 77 + 143 = 220 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );