document.write( "Question 831195: Driving to Michigan State University, Tiffany drove 53 mph for 2 hours and then drove 67 mph for 5 hours. What is Tiffany's average rate of speed, in mph, for her trip? \n" ); document.write( "
Algebra.Com's Answer #501206 by wth12345(3)![]() ![]() ![]() You can put this solution on YOUR website! 53/2 for the first mph which is 26.5mph \n" ); document.write( "67/5 for the second mph which is 13.4mph \n" ); document.write( "Asking for a average would be 26.5+13.4 which is 39.9 which than you divide considering there asking for the average which would be 39.9/7 which =5.7mph \n" ); document.write( " |