document.write( "Question 830952: A quantity a varies directly as x and another quantity b varies inversely as x. when x = 2, then sum of a and b is 7, and when x = 3, the sum is 8. Find the value of a+b when x = 4. \n" ); document.write( "
Algebra.Com's Answer #501204 by ankor@dixie-net.com(22740)\"\" \"About 
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A quantity a varies directly as x
\n" ); document.write( "a = kx
\n" ); document.write( " and another quantity b varies inversely as x.
\n" ); document.write( "b = k/x
\n" ); document.write( " when x = 2, then sum of a and b is 7,
\n" ); document.write( "a + b = 7
\n" ); document.write( "Replace a and b
\n" ); document.write( "kx + k/x = 7
\n" ); document.write( "replace x with 2
\n" ); document.write( "2k + k/2 = 7
\n" ); document.write( "find k, multiply equation by 2
\n" ); document.write( "4k + k = 14
\n" ); document.write( "5k = 14
\n" ); document.write( "k = 14/5
\n" ); document.write( "k = 2.8
\n" ); document.write( ":
\n" ); document.write( "and when x = 3, the sum is 8.
\n" ); document.write( "2.8x + 2.8/x = 8
\n" ); document.write( "2.8(3) + 2.8/3 = 9.333 !!!
\n" ); document.write( "I just can't make this work\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Find the value of a+b when x = 4.
\n" ); document.write( "
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