document.write( "Question 70282: A room is 1.5 times long as it is wide and its perimeter is 25 meters. find the dimension of the room? \n" ); document.write( "
Algebra.Com's Answer #50120 by bucky(2189)\"\" \"About 
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Two equations are required.\r
\n" ); document.write( "\n" ); document.write( "You know that the perimeter of a rectangle is given by adding a length, a width, another length,
\n" ); document.write( "and another width to get the perimeter.\r
\n" ); document.write( "\n" ); document.write( "Let L represent the Length, W represent the Width, and P represent the Perimeter of the
\n" ); document.write( "rectangle. With this notation, the equation for the perimeter of the rectangle is:
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\n" ); document.write( "\"P+=+L+%2B+W+%2B+L+%2B+W\"
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\n" ); document.write( "This simplifies to:
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\n" ); document.write( "\"P+=+2%2AL+%2B+2%2AW\"
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\n" ); document.write( "The problem gives the perimeter as 25 meters. Substitute this:
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\n" ); document.write( "\"25+=+2%2AL+%2B+2%2AW\"
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\n" ); document.write( "The problem also says that the length is 1.5 times the width. In equation form, this is:
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\n" ); document.write( "\"L+=+1.5%2AW\"
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\n" ); document.write( "Substitute this in place of L in the perimeter equation:
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\n" ); document.write( "\"25+=+2%2A1.5%2AW+%2B+2%2AW\"
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\n" ); document.write( "Multiply out the first term on the right side:
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\n" ); document.write( "\"25+=+3%2AW+%2B+2%2AW\"
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\n" ); document.write( "and combine the two terms on the right side to get:
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\n" ); document.write( "\"25+=+5%2AW\"
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\n" ); document.write( "Divide both sides by 5 and you find that
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\n" ); document.write( "\"W+=+5+meters\"
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\n" ); document.write( "And since the length is 1.5 times as long, the length is:
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\n" ); document.write( "\"L+=+1.5%2A5+=+7.5+meters\"
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\n" ); document.write( "Check it. \r
\n" ); document.write( "\n" ); document.write( "\"P+=+7.5+%2B+5+%2B+7.5+%2B+5+=+25+meters\"
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\n" ); document.write( "The answer checks.
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\n" ); document.write( "Hope this helps you to understand the problem.\r
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