document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831179>Question 831179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to complete a fraction Magic Square.  I must find out what \"x\" equals on each row and column of the square.  I am given for the first row:  x, -1/6 and 0; on the second row: -1/2, x, and 5/6; on the third row:1/3, x, and -1/3.  I must find the fraction sum equaling the same number horizontally, vertically, and diagonally.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501195 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x  , -1/6, 0<BR>\n" );
document.write( "1/2, x  , 5/6<BR>\n" );
document.write( "1/3, x,  -1/3<BR>\n" );
document.write( "the third column adds up to 5/6-2/6=3/6=1/2<BR>\n" );
document.write( "the third row is 0 with out x so x must be 1/2<BR>\n" );
document.write( "1st row x-1/6+0=a, a-x=-1/6<BR>\n" );
document.write( "2nd row 1/2+x+5/6=a,a-x=8/6<BR>\n" );
document.write( "3rd row 1/3+x-1/3=a, a-x=0<BR>\n" );
document.write( "They are not consistent.<BR>\n" );
document.write( "There is no solution.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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