document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831151>Question 831151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the  length  of  the  rectangle  is  4 cm more than  its  breadth . If the  perimeter  of  the  rectangle  is  192  cm , find  the  length  and  breadth of  the  rectangle .\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501169 by </B><A HREF=/tutors/aboutme.mpl?userid=vaibhavaggarwal29><B>vaibhavaggarwal29(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vaibhavaggarwal29><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vaibhavaggarwal29><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501169\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of Rectangle = 2(l+b)<BR>\n" );
document.write( "Let the breath of rectangle be x cm.<BR>\n" );
document.write( "Then, Length = (x+4) cm<BR>\n" );
document.write( "192 = 2(x+x+4)<BR>\n" );
document.write( "192=2(2x+4)<BR>\n" );
document.write( "96 = 2x + 4<BR>\n" );
document.write( "92 = 2x<BR>\n" );
document.write( "x = 46 <BR>\n" );
document.write( "Breath = 46 cm<BR>\n" );
document.write( "Length = 50 cm  Answer </SPAN>\n" );
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