document.write( "Question 831092: the difference of two integers is 9. five times the smaller is 9 more than three times the larger. find the integers.
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Algebra.Com's Answer #501141 by JulietG(1812)\"\" \"About 
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Let A be the larger integer, and B be the smaller integer.
\n" ); document.write( "A - 9 = B
\n" ); document.write( "5B = 3A + 9
\n" ); document.write( "Multiply the top equation by 5 to make it easier to work with.
\n" ); document.write( "5A - 45 = 5B
\n" ); document.write( "Substitute the values from the top equation into the bottom
\n" ); document.write( "(5A - 45) [this WAS 5B in the equation] = 3A + 9
\n" ); document.write( "5A - 45 = 3A + 9
\n" ); document.write( "Subtract 3A from each side
\n" ); document.write( "2A - 45 = 9
\n" ); document.write( "Add 45 to each side
\n" ); document.write( "2A = 54
\n" ); document.write( "Divide each side by 2
\n" ); document.write( "A = 27 <<--
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\n" ); document.write( "Let's make sure it's right by putting it back into the original question.
\n" ); document.write( "\"the difference of two integers is 9.\" Therefore, B = 27-9, or 18. <<--
\n" ); document.write( "\"five times the smaller is 9 more than three times the larger\" (5*18) = (3*27) +9
\n" ); document.write( "90 = 81 + 9
\n" ); document.write( "90 = 90
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