document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=831077>Question 831077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of angles is 90 degrees.the angles are in the ratio 2:3 find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #501124 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=501124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming these are two complementary angles.<BR>\n" );
document.write( "Let A be the larger angle.<BR>\n" );
document.write( "Let B be the smaller angle.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "We're told in the problem the following:<BR>\n" );
document.write( "A + B = 90<BR>\n" );
document.write( "A:B = 3:2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "The easiest way to do this is to see that the ratio contains \"5\".  Divide the sum of the angles.<BR>\n" );
document.write( "90/5 = 18<BR>\n" );
document.write( "Then multiply the ratio.<BR>\n" );
document.write( "18*2 and 18:3<BR>\n" );
document.write( "36:54 is the same ratio as 2:3<BR>\n" );
document.write( "36+54 = 90<BR>\n" );
document.write( "Success! </SPAN>\n" );
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