document.write( "Question 831075: Michelle is three times as old as Fiona. Fiona is twice as old as Madeline. Madeline is seven years old. How old is Michelle?\r
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document.write( " a. 42 years old
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document.write( " b. 14 years old
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document.write( " c. 21 years old
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document.write( " d. 12 years old
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Algebra.Com's Answer #501119 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Let B = Moochelle's age \n" ); document.write( "Let F = Fiona's age \n" ); document.write( "Let M = Madeline's age \n" ); document.write( ". \n" ); document.write( "Here's the information from the question: \n" ); document.write( "B = 3F (Michelle is three times as old as Fiona) \n" ); document.write( "F = 2M (Fiona is twice as old as Madeline) \n" ); document.write( "M = 7 (Madeline is seven years old) \n" ); document.write( ". \n" ); document.write( "If F is 2M, then F = 2*7 = 14 \n" ); document.write( "Since B is 3F, and we know F to be 14, multiply 3*14 to get \n" ); document.write( "42 <<-- \n" ); document.write( " |