document.write( "Question 831075: Michelle is three times as old as Fiona. Fiona is twice as old as Madeline. Madeline is seven years old. How old is Michelle?\r
\n" ); document.write( "\n" ); document.write( " a. 42 years old
\n" ); document.write( "
\n" ); document.write( " b. 14 years old
\n" ); document.write( "
\n" ); document.write( " c. 21 years old
\n" ); document.write( "
\n" ); document.write( " d. 12 years old
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #501119 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
Let B = Moochelle's age
\n" ); document.write( "Let F = Fiona's age
\n" ); document.write( "Let M = Madeline's age
\n" ); document.write( ".
\n" ); document.write( "Here's the information from the question:
\n" ); document.write( "B = 3F (Michelle is three times as old as Fiona)
\n" ); document.write( "F = 2M (Fiona is twice as old as Madeline)
\n" ); document.write( "M = 7 (Madeline is seven years old)
\n" ); document.write( ".
\n" ); document.write( "If F is 2M, then F = 2*7 = 14
\n" ); document.write( "Since B is 3F, and we know F to be 14, multiply 3*14 to get
\n" ); document.write( "42 <<--
\n" ); document.write( "
\n" );