document.write( "Question 831055: a tank holds 20 L of a chemical solution, with a current strength of 60%. how much must be replaced with 100% solution to get a final strength of 80% \n" ); document.write( "

Algebra.Com's Answer #501105 by josgarithmetic(39617) $\"\"$ $\"About$

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This is only a partial explanation for solving the example problem.\r
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\n" ); document.write( "\n" ); document.write( "Remove and replace a volume quantity, v liters of the solution in the tank.
\n" ); document.write( " $\"20%2A0.60-v%2A0.60\"$ is the amount of chemical ( as if 100%) in the tank; then will add to maintain the original volume with the pure solution at 100% strength, so you will have $\"20%2A0.60-v%2A0.60%2Bv%2A1.00\"$ amount of pure chemical in the tank.\r
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\n" ); document.write( "\n" ); document.write( "Working with the accounting of pure chemical in the solution in the tank,
\n" ); document.write( " $\"20%2A0.6-v%2A0.6%2Bv%2A1\"$
\n" ); document.write( " $\"20%2A0.6-v%2A0.6%2Bv\"$
\n" ); document.write( " $\"20%2A0.6%2Bv-0.6%2Av\"$
\n" ); document.write( " $\"20%2A0.6%2B%281-0.6%29v\"$
\n" ); document.write( " $\"20%2A%280.6%29%2B%280.4%29v\"$ , amount of resulting pure chemical in the tank \n" ); document.write( "

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