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document.write( "(-6, 8)\r\n" );
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document.write( "That means this interval:\r\n" );
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document.write( "-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10\r\n" );
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document.write( "locate the mid point of this interval by averaging -6 and 8\r\n" );
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\r\n" );
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document.write( "So 1 in the exact middle of that interval. I'll mark it M\r\n" );
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document.write( "-------(====================M====================)------\r\n" );
document.write( "-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10\r\n" );
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document.write( "The interval (-6,8) contains all the points up to 8-1 or 7 units\r\n" );
document.write( "to the right of M=1 and all the points up to 1-(-6) or 7 units to\r\n" );
document.write( "the left of M=1.\r\n" );
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document.write( "Let x be any point on the interval. \r\n" );
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document.write( "If x is to the right of 1, if you subtract 1 from it, x-1, you\r\n" );
document.write( "will always get a number between 0 and 6.\r\n" );
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document.write( "If x is to the left of 1, if you subtract 1 from it, x-1, you\r\n" );
document.write( "will always get a number between -6 and 0.\r\n" );
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document.write( "So you combine the two preceding statements by saying:\r\n" );
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document.write( "If x is on the interval, regarless of whether it's to the right or left\r\n" );
document.write( "of -1, if you subtract 1 from it, x-1 AND TAKE THE ABSOLUTE VALUE of it,\r\n" );
document.write( "|x-1|, it will always be between 0 and 6, so\r\n" );
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document.write( " |x-1|<6 is the answer.\r\n" );
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document.write( "If you want a formula, \r\n" );
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document.write( "(a,b) is equivalent to 

\r\n" );
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document.write( "If you want to go the other way,\r\n" );
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document.write( "|x-h| < k (if k > 0) is equivalent to h-k < x < h+k\r\n" );
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document.write( "--------------------------------------------------\r\n" );
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document.write( "Using \"oo\" for \"infinity\",\r\n" );
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document.write( "(-oo,a) U (b,oo) (if a < b) is equivalent to 

\r\n" );
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document.write( "|x-h| > k (if k > 0), is equivalent to \" x < h-k OR x > h+k \".\r\n" );
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document.write( "Edwin
\r
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