document.write( "Question 831014: Four men working together can dig a trench in 42 days. They begin the job, but one worker works only 1/2 days. How long will it take to complete the job? \n" ); document.write( "
Algebra.Com's Answer #501063 by josmiceli(19441)\"\" \"About 
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The rate for 4 men is 1 trench in 42 days
\n" ); document.write( "Let \"+x+\" = the fraction of a trench dug
\n" ); document.write( "by 4 men in 1/2 day
\n" ); document.write( "\"+1%2F42+%2B+x%2F%28%281%2F2%29%29+\"
\n" ); document.write( "\"+1%2F42+=+2x+\"
\n" ); document.write( "\"+x+=+1%2F84+\"
\n" ); document.write( "----------------
\n" ); document.write( "That means there is \"+1+-+1%2F84+=+83%2F84+\"
\n" ); document.write( "of a trench left to dig after 1/2 day
\n" ); document.write( "----------------
\n" ); document.write( "3 men have to finish the job
\n" ); document.write( "If 4 men take 42 days to dig a trench,
\n" ); document.write( "1 man takes 4 times as long, or \"+4%2A42+=+168+\" days
\n" ); document.write( "3 men take 1/3 of that time, or 56 days
\n" ); document.write( "Let \"y\" = the number of days for 3
\n" ); document.write( "men to dig \"+83%2F84+\" of the trench
\n" ); document.write( "\"+1%2F56+=+%28+83%2F84%29%2Fy+\"
\n" ); document.write( "\"+y%2A%28+1%2F56+%29+=+83%2F84+\"
\n" ); document.write( "\"+y+=+%28+56%2A83%29+%2F+84+\"
\n" ); document.write( "\"+y+=+4648%2F84+\"
\n" ); document.write( "\"+y+=+55.333+\"
\n" ); document.write( "It will take \"+.5+%2B+55.333+=+55.5333+\" days
\n" ); document.write( "to finish the job
\n" ); document.write( "----------------------
\n" ); document.write( "Hope I got it\r
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